y/5=10 ….?
wht should be added to -7/3 to get 3/7..
Question
y/5=10 ….?
wht should be added to -7/3 to get 3/7..
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Answers ( )
Answer:
Y=50
Y=10*5
Y=50
If we were supposed to find the value of Y
(2)
-7/3+x=3/7
x=3/7+7/3
58/21
Answer:
=>y/5=10
=>y=10×5
=>y=50
.
. . y=50
* Let the number be X
now,
=> -7/3 + x = 3/7
=> x = 3/7 –(–7/3)
=> x = 3/7 + 7/3
=> x = (9+49)/21
=> x = 58/21
.
. . The number is 58/21.