y
4
(4) 5x – 3y = 0, 3x – 5y = 16
3. Solve the following pairs of linear equations
by the method of substituti

Question

y
4
(4) 5x – 3y = 0, 3x – 5y = 16
3. Solve the following pairs of linear equations
by the method of substitution :
(1) + = 5, +3
= 7
(2) * – 빛 = 5, + = 17
5x
3y
y
(3) + : 43,
= 8
4
5
7
쁨
= 5
3
5 2.​

Jezebel 1 year 2021-08-19T19:08:07+00:00 0

Answers ( )

  1. Eirlys
    0
    2021-08-19T19:09:16+00:00
    Reply

    Answer:

    5x-3y=0 — (i)

    3x-5y=0 –(ii)

    By substitutional method

    From equation (i)

    5x-3y=0

    5x=3y

    From equation (ii)

    3x-5y=0

    3(3y)-5y=0

    9y-5y=0

    4y=0

    y=1/4

    From equation (i)

    5x=3y

    5x=3(1/4)

    x=3/4X5

    x=15/4

    Final answer is

    X=15/4

    Y=1/4

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