##
y

4

(4) 5x – 3y = 0, 3x – 5y = 16

3. Solve the following pairs of linear equations

by the method of substituti

Question

y

4

(4) 5x – 3y = 0, 3x – 5y = 16

3. Solve the following pairs of linear equations

by the method of substitution :

(1) + = 5, +3

= 7

(2) * – 빛 = 5, + = 17

5x

3y

y

(3) + : 43,

= 8

4

5

7

쁨

= 5

3

5 2.

## Answers ( )

Answer:5x-3y=0 — (i)

3x-5y=0 –(ii)

By substitutional method

From equation (i)

5x-3y=0

5x=3y

From equation (ii)

3x-5y=0

3(3y)-5y=0

9y-5y=0

4y=0

y=1/4

From equation (i)

5x=3y

5x=3(1/4)

x=3/4X5

x=15/4

Final answer is

X=15/4

Y=1/4