A train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. How far will it travel in his time​

Question

A train travelling at 30 ms -1. accelerates at 0.5ms-1 for 30s. How far will it travel in his time​

Sigourney 2 years 2021-08-30T09:47:08+00:00 0

Answers ( )

  1. Verity
    0
    2021-08-30T09:48:55+00:00
    Reply

    1125 m (1.125 km)

    Explanation:

    Given –

    A train travelling at 30 m/s, accelerates at 0.5 m/s² for 30s. How far will it travel in this time ?

    Solution –

    From the given question we can say,

    initial speed (u) = 30 m/s

    Acceleration (a) = 0.5 m/s²

    Time taken (t) = 30 s

    Distance traveled (s) = ?

    Using formula,

    \sf \: s = ut + \frac{1}{2} a {t}^{2}

    we can find the distance.

    [put the value of u, t and a]

    \sf = > s = (30 \times 30) + ( \frac{1}{2} \times 0.5 \times 3 {0}^{2} ) \\ \\ = > \sf 900 + ( \frac{1}{ \cancel{2} } \times \frac{1}{ \cancel{2}} \times \cancel{30}^{15} \times { \cancel{30}}^{15} ) \\ \\ = > \sf900 + (15 \times 15) \\ \\ = > \sf900 + 225 \\ \\ = > \sf1125 \: m

    Hence the train will travel 1125 metres in this time.

    hope it helps.

  3. Dilys
    0
    2021-08-30T09:48:57+00:00
    Reply

    Answer:

    The required answer is 1125 m

    Explanation:

    Given :

    A train travelling at 30 m/s accelerates at 0.5 m/s² for 30 s.

    To find :

    the distance travelled

    Solution :

    initial velocity, u = 30 m/s

    acceleration, a = 0.5 m/s²

    time taken, t = 30 s

    distance travelled, s = ?

    Using  \bf s=ut+\dfrac{1}{2}at^2,

    \rm s=30(30)+\dfrac{1}{2}(0.5)(30^2) \\\\ \rm s=900+\dfrac{900}{4} \\\\ \rm s=900+225 \\\\ \rm s=1125 \ m

    Therefore, the distance travelled is 1125 m.

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